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x^2+.25x+.015=0
We add all the numbers together, and all the variables
x^2+.25x+0.015=0
a = 1; b = .25; c = +0.015;
Δ = b2-4ac
Δ = .252-4·1·0.015
Δ = 0.0025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.25)-\sqrt{0.0025}}{2*1}=\frac{-0.25-\sqrt{0.0025}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.25)+\sqrt{0.0025}}{2*1}=\frac{-0.25+\sqrt{0.0025}}{2} $
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